While there are lots of femme fatales throughout cinema history, Sigourney Weaver & Linda Hamilton in T2 were the Sci Fi heroine extraordinaires that are still hard to beat to this day IMO. Theron's Furiosa probably deserves to occupy the #3 spot on the tough-as-nails female roles.

Timestamps and films

0:00 28 Days Later
0:35 The Matrix
0:50 The Terminator
1:04 T2
1:09 Predator
1:12 Die Hard
1:25 Face Off
1:30 Predator
1:45 Die Hard
1:55 Rambo (not sure which one)
2:08 Die Hard
2:18 The Professional
2:35 Captain America: The Winter Soldier
3:22 Star Wars The Phantom Menace
3:28 Star Wars A New Hope
3:37 Star Wars The Empire Strikes Back
3:43 Die Hard
3:44 Platoon
3:46 Invasion of the Body Snatchers
3:56 Aliens
4:10 Highlander
4:44 The Right Stuff
5:14 Minority Report
5:19 Disclosure
5:38 2001 A Space Odyssey
5:56 Blade Runner
6:15 Patton
6:29 A Few Good Men
6:43 The Breakfast Club
7:06 Rain Man
7:20 Ghost
7:42 An Officer and a Gentleman
7:55 My Dinner with Andre
8:14 Sixteen Candles
8:18 Lost in Translation
8:23 Star Wars The Empire Strikes Back
8:35 Good Will Hunting
8:58 An American Tale
9:08 The Shinning
9:20 LOTR: The Two Towers
9:43 MTV- The Real World: Seattle
10:04 House Party
10:09 The Color of Money
10:14 Pulp Fiction
10:22 The Breakfast Club
10:26 Zardoz
10:29 Blazzing Saddles
10:32 MIB
10:34 Hook
10:36 The Beastmaster
10:41 Wallstreet
10:44 The Shawshank Redemption
10:51 The Fugitive
10:55 Pulp Fiction
11:10 The Ring
11:12 Vertigo
11:14 National Lampoon’s Vacation
11:35 Animal House
12:31 Good Will Hunting
12:44 Dead Poets Society

Good T2 clip. Please submit it!

Well... the cliché is as old as cinema, true, BUT, if there's THE one female badass that truly would behave as such IRL, it would be Post-T2 Sarah Connor, isn't it? Both character (Sarah) AND actress (Linda Hamilton) EARNED the "calmly walk away from explosions" shtick in my book.

The All-time Greatest On-Screen Female Badass #1 & #2 gotta be between Sarah Connor or Ripley from Alien. For me I'd pick Sarah as #1. My jaw dropped so hard seeing the changes of Hamilton from T1 to T2. Freaking amazing.

The thumbnail image for this video has been updated - thumbnail added by BSR.

I guess we can partially thank James Cameron (T2) for this brilliance ?

Ok, so every video I've watched on this still seems to take the view that both laps are the same distance. If that's the case then it's impossible (T2 = 0, etc).

But a lap is just a revolution of the track, you don't have to run at a fixed radius (and therefore a fixed circumference).

If you increase the distance (even by a tiny amount), it is possible.
If the 1st lap is 100m and you run it in 100s, then you get 1m/s. If the second lap is 200m, then you would need to run that in 50s (V1 = 1m/s, Vavg = 2m/s, 300m @ 2m/s = 150s, 150s - 100s (for the lap you've already run).

So if you double the distance, you need to run 4 times faster.
If you triple the distance, you need to run 3 times faster.
If you run 10 times the distance, you need to run 2.2222m/s

Basically the bigger your lap the slower you can go approaching 2m/s.

Conversely, the smaller the difference the faster you need to go (e.g. for 101m, you would need to do the 2nd lap at 202m/s or around 450mph )

Oh, and the bike CAN go forwards, you just need a ridiculously low gear.

This line is incorrect Vavg = (V1+V2)/2. That only applies if you run at V1 and V2 FOR THE SAME AMOUNT OF TIME.

Speed is Distance divided by Time, so the formula for calculating average speed is Dtotal / Ttotal.

The problem is that that only works if your second lap can be longer than the first lap.

If they are the same distance, the maths are undefined.

V1 = D1/T1
V2 = D2/T2

Vavg = (D1+D2)/(T1+T2)
if (D1 = D2) then
Vavg = 2D1/(T1+T2)

if Vavg = 2V1 then
2D1/T1 = 2D1/(T1+T2)
then T2 = 0

therefore V2 = D1/0 .... cannot divide by 0 (and no, it's not infinity )

1) < 1/2 full of honey or other slime
2) bike will go backwards 1/4 pedal turn (forcing the pedal to rotate forward but move backwards) regardless of gearing because the wheel rotation/travel is much longer than the pedal rotation/travel

3) (T1+T2)/2 can never equal or be less than (T1)/2...so impossible unless you can finish lap 2 before you start it

4) a small portion of the lip of the wheels, farther out than the part that rides on the rail

Side note, how did you all get the numbers mixed up? #2 is the bike, not the track.

1) Some sort of viscous liquid, like honey.
2) Yeah... I thought v1=1 and v2=3, but then I realised that was actually more like t1=3, t2=1 which is not quite what the question asked.
3) Most of the bike will go forwards.
4) First thought was the wheels, but it would only ever be the very outside edge of the wheel in contact with the ground, only on driven wheels, and only if the wheel was slipping.

edit. I knew there was a reason it had to be a train and not a car. The rims of the train wheels extend past the contact point with the rails, so they will be moving backwards (well, part of them) even if the wheels don't slip.

Your video, Robert Patrick Recreates His "T2" Look - CONAN on TBS, has made it into the Top 15 New Videos listing. Congratulations on your achievement. For your contribution you have been awarded 1 Power Point.

Someone needs to photoshop some T-1000 spikey metallic arms on that guy, and change the music to T2:JD

(yeah I watched that movie way too much as a kid, and I see it everywhere)

That's an EC145 T2, isn't it?

A2, T1 and T2 are all the same too. It could be argued they are ALL chase/survival horror movies. I think we know what scares Cameron.