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Irishman (Member Profile)

MycroftHomlz says...

Yes.

http://wtc.nist.gov/pubs/factsheets/faqs_8_2006.htm

Go to 6. There is the answer.

Right, so let me know if I lose you, and I will try to make it more clear-

The basic idea is that as the mass collapsed the initial collapsing floors collapsed at a total acceleration less than gravity at STP. At the floors collapsed onto each other their total momentum increased.

Or an easier way to see it,

F= (M+dm)*a = (M+dm)*g_STP-Fimpulse

Here I represented the force downward as an increasing quantity and Fimpulse as the force due to the collision of the total mass at time t-1 to time t. So, as the mass falls it gains more mass, until eventually the total force of the mass falling can be approximated F~(M+dm)g_STP.

Not that more mass falls at a faster rate, rather as more mass falls the effect of the other forces becomes negligible.

This means that for the most part the acceleration can be effectively described by something in freefall, and hence g_STP~a.

Note Fimpulse is a constant as a function of time.
In reply to this comment by Irishman:
I back Choggie's comments.

My own thoughts,
The thermite theory addressed the problem of the freefall speed of the tower's collapse.

There is still no official or third party theory that addresses that problem.

A freefall speed of collapse explicity implies no resistance, and that is impossible for 3 of the buildings that collapsed at freefall speed unless they were demolished.

If someone can explain how the freefall collapses were caused by the fire, then they will have solved the riddle.

Debunking the Thermite Theory: 911 Consipiracy

MycroftHomlz says...

Yes.

http://wtc.nist.gov/pubs/factsheets/faqs_8_2006.htm

Go to 6. There is the answer.

Right, so let me know if I lose you, and I will try to make it more clear-

We must agree that as the floors collapsed onto each other the total momentum of the falling object increases. We can express this as a force equation, in the following way-

F= (M+dm)*a = (M+dm)*g_STP-Fimpulse

Here I represented the force downward as an increasing quantity and Fimpulse as the force due to the collision of the total mass at time t-1 to time t. So, as the mass falls it gains more mass, until eventually the total force of the mass falling can be approximated F~(M+dm)g_STP.

Not that more mass falls at a faster rate, rather as more mass falls the effect of the other forces becomes negligible.

This means that for the most part the acceleration can be effectively described by something in freefall, and hence g_STP~a.

Note:
Fimpulse is a constant as a function of time.
g_STP is gravity at Standard Temperature and Pressure, which is negligibly different than g in a vacuum.

Bill O'Reilly vs. David Letterman, Round 2 - Oct 27,2006

Farhad2000 says...

The winning question is completely dubious, either answer is wrong? If you say we are winning you basically condone the lives lost thus far, if you say we are losing you make the entire conflict seem like a waste. WTF?

You won't have Ol' Dag to kick around anymore (Sift Talk Post)

Krupo says...

While the demands of the bank account can't be overlooked, we'll nevertheless miss you in whatever capacity we're losing you - say that you'll still be around in *some* capacity - right dag?

Sifters never go away, they just show up with less frequency!

Congrats and thanks for everything you deserve praise and gratitude for, and good luck in whatever you find yourself doing next!

Sugar Gliders are cool!



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